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NCERT Solutions Class 10 Mathematics Solutions for Probability - Exercise 15.1 in Chapter 15 - Probability

Question 51 Probability - Exercise 15.1

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Figure), and these are equally likely outcomes. What is the probability that it will point at 8?

Question 51 Image - NCERT Solutions - Mathematics , Class 10 chapter Probability

Answer:

Total number of possible outcomes = 8

P(E) = (Number of favourable outcomes/ Total number of outcomes)

Total number of favourable events (i.e. 8) = 1

∴ P (pointing at 8) = ⅛ = 0.125

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