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NCERT Solutions Class 10 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.1 in Chapter 13 - Surface Areas and Volumes
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A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.
Answer:
The diagram is as follows:
Now, the diameter of hemisphere = Edge of the cube = l
So, the radius of hemisphere = l/2
∴ The total surface area of solid = surface area of cube + CSA of hemisphere – Area of base of hemisphere
TSA of remaining solid = 6 (edge)2+2πr2-πr2
= 6l^2+ πr^2\\ = 6l^2+π(\frac{l}{2})^2\\ = 6l^2+π\frac{l^2}{4}\\ = \frac{l^2}{4}(24+π)\ \text{sq. units}
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