NCERT Solutions Class 10 Mathematics Solutions for Areas Related to Circles - Exercise 12.2 in Chapter 12 - Areas Related to Circles

Question 11 Areas Related to Circles - Exercise 12.2

A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal sectors as shown in figure. the area of each sector of the brooch.

Question 11 Image - NCERT Solutions - Mathematics , Class 10 chapter Areas Related to Circles


Diameter (D) = 35 mm

Total number of diameters to be considered= 5

Now, the total length of 5 diameters that would be required = 35×5 = 175

Circumference of the circle = 2πr

C = πD = \frac{22}{7}×35 = 110\\ \text{Area of the circle} = πr^2\\ Or, A = (\frac{22}{7})×(\frac{35}{2})^2 = \frac{1925}{2} mm^2\\ \text{Total Number of sectors in the brooch} = 10\\ \text{So, the area of each sector = total area of the circle/number of sectors}\\ ∴ \text{Area of each sector}= (\frac{1925}{2})×\frac{1}{10} = \frac{385}{4} mm^2\\

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