NCERT Solutions Class 10 Mathematics Solutions for Areas Related to Circles - Exercise 12.2 in Chapter 12 - Areas Related to Circles

Question 11 Areas Related to Circles - Exercise 12.2

A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal sectors as shown in figure. the area of each sector of the brooch.

Diameter (D) = 35 mm

Total number of diameters to be considered= 5

Now, the total length of 5 diameters that would be required = 35×5 = 175

Circumference of the circle = 2πr

C = πD = \frac{22}{7}×35 = 110\\ \text{Area of the circle} = πr^2\\ Or, A = (\frac{22}{7})×(\frac{35}{2})^2 = \frac{1925}{2} mm^2\\ \text{Total Number of sectors in the brooch} = 10\\ \text{So, the area of each sector = total area of the circle/number of sectors}\\ ∴ \text{Area of each sector}= (\frac{1925}{2})×\frac{1}{10} = \frac{385}{4} mm^2\\

Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!