Jump to

**A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding major sector. (Use π = 3.14) **

Answer:

Here AB be the chord which is subtending an angle 90° at the center O.

It is given that the radius (r) of the circle = 10 cm

Area of major sector = Area of circle – Area of minor sector

= (3.14×10^{2})-78.5

= 235.5 cm^{2}

Related Questions

Was This helpful?

Exercises

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved