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Triangles | Triangles - Exercise 6.4

Question 9

A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.

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Let MN = 18 m be the flag pole and its shadow be LM = 9.6 m.

The distance of the top of the pole, N from the far end, L of the shadow is LN.

In right angled ∆LMN,

LN2 = LM2 + MN2 [[by Pythagoras theorem]]

⇒ LN2 = (9.6)2 + (18)2

⇒ LN2 = 9.216 + 324

⇒ LN2 = 416.16

∴ LN = √416.16 = 20.4 m

Hence, the required distance is 20.4 m

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subject-cta

Question 9

A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Let MN = 18 m be the flag pole and its shadow be LM = 9.6 m.

The distance of the top of the pole, N from the far end, L of the shadow is LN.

In right angled ∆LMN,

LN2 = LM2 + MN2 [[by Pythagoras theorem]]

⇒ LN2 = (9.6)2 + (18)2

⇒ LN2 = 9.216 + 324

⇒ LN2 = 416.16

∴ LN = √416.16 = 20.4 m

Hence, the required distance is 20.4 m

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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