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Real Numbers | Real Numbers Exercise 1.3

Question 10

12^n (n is any natural number), cannot end with which of the following digits?

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Number ending at 0 or 5 is divisible by 5.

Now, \left(12\right)^n=\left(2\times2\times3\right)^n=2^{2n}\times3^n

It does not have 5 in prime factorisation. So, 12^n can never end with 5 and zero.

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Question 10

12^n (n is any natural number), cannot end with which of the following digits?

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Number ending at 0 or 5 is divisible by 5.

Now, \left(12\right)^n=\left(2\times2\times3\right)^n=2^{2n}\times3^n

It does not have 5 in prime factorisation. So, 12^n can never end with 5 and zero.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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