A child’s game has 8 triangles of which 3 are blue and rest are red, and 10 squares of which 6 are blue and rest are red. One piece is lost at random. Find the probability that it is a square of blue colour.
Total no. of triangles = 8
Triangles with blue colour = 3
Triangles with red colour = 8 – 3 = 5
Total no. of squares = 10
Squares with blue colour = 6
Squares with red colour = 10 – 6 = 4
Number of favourable outcomes for the events that lost figure is square of blue colour
i.e., F(E) = 6
T(E) = 18
P(E) (getting a blue square) = P(E) = \frac{\mathrm{F}(\mathrm{E})}{\mathrm{T}(\mathrm{E})}=\frac{6}{18}=\frac{1}{3}
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