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NCERT Exemplar Solutions Class 10 Mathematics Solutions for Statistics and Probability - Exercise 13.3 in Chapter 13 - Statistics and Probability
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A bag contains 10 red, 5 blue and 7 green balls. A ball is drawn at random, Find the probability of this ball being a green ball .
Answer:
No. of red balls = 10
Number of blue balls = 5
Number of green balls = 7
Total number of balls T(E) = (10 + 5 + 7) = 22
Number of favourable outcomes of getting a green ball = F(E) = 7
\mathrm{P}(\mathrm{E})=\frac{\mathrm{F}(\mathrm{E})}{\mathrm{T}(\mathrm{E})}=\frac{7}{22}
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