A coin is tossed 3 times. List the possible outcomes, find the probability of getting at least two heads .
Total number of possible outcomes when if a coin is tossed
Number of favourable outcomes of getting (HHH), (HHT), (HTH), (THH) (TTT) (TTH) (THT) (HTT)
T(E) = 8
Number of favourable outcomes of getting at least 2 heads
F(E) = 4
P(E)=\frac{F(E)}{T(E)}=\frac{4}{8}=\frac{1}{2}
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