Jump to
NCERT Exemplar Solutions Class 10 Mathematics Solutions for Statistics and Probability - Exercise 13.3 in Chapter 13 - Statistics and Probability
Prev
The weight of coffee in 70 packets are shown in the following table :
| Weight (in g) | Number of packets |
|---|---|
| 200-201 | 12 |
| 201-202 | 26 |
| 202-203 | 20 |
| 203-204 | 9 |
| 204-205 | 2 |
| 205-206 | 1 |
Determine the modal weight.
Answer:
In the given data, the highest frequency is 26, which lies in the interval 201 – 202
Here, l = 201,fm = 26,f1 = 12,f2 = 20 and (class width) h = 1
\therefore \text { Mode }=1+\left(\frac{f_{m}-f_{1}}{2 f_{m}-f_{1}-f_{2}}\right) \times h \\ \left.=201+\frac{26-12}{(2 \times 26-12-20}\right) \times 1 \\ =201+\frac{14}{(52-32)} \\ =201+14 / 20 \\ =201+0.7 \\ =201.7 \mathrm{~g}
Hence, the modal weight = 201.7 g.
Related Questions
Facebook
Whatsapp
Copy Link
Exercises
Chapters
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved