# NCERT Exemplar Solutions Class 10 Mathematics Solutions for Statistics and Probability - Exercise 13.3 in Chapter 13 - Statistics and Probability

Question 5 Statistics and Probability - Exercise 13.3

The weight of coffee in 70 packets are shown in the following table :

Weight (in g) Number of packets
200-201 12
201-202 26
202-203 20
203-204 9
204-205 2
205-206 1

Determine the modal weight.

In the given data, the highest frequency is 26, which lies in the interval 201 – 202

Here, l = 201,fm = 26,f1 = 12,f2 = 20 and (class width) h = 1

\therefore \text { Mode }=1+\left(\frac{f_{m}-f_{1}}{2 f_{m}-f_{1}-f_{2}}\right) \times h \\ \left.=201+\frac{26-12}{(2 \times 26-12-20}\right) \times 1 \\ =201+\frac{14}{(52-32)} \\ =201+14 / 20 \\ =201+0.7 \\ =201.7 \mathrm{~g}

Hence, the modal weight = 201.7 g.

Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!