# NCERT Exemplar Solutions Class 10 Mathematics Solutions for Statistics and Probability - Exercise 13.1 in Chapter 13 - Statistics and Probability

Question 1 Statistics and Probability - Exercise 13.1

Consider the following frequency distribution:

Class 1 - 5 6 - 10 11 - 15 16 - 20 21 - 25
Frequency 13 10 15 8 11

The upper limit of the median class is

According to the question,

Classes are not continuous, hence, we make the data continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.

Class Frequency (f) Cumulative Frequency
0.5 - 5.5 13 13
5.5 - 10.5 10 13 + 10 = 23
10.5 - 15.5 15 23 + 15 = 38
15.5 - 20.5 8 38 + 8 = 46
20.5 - 25.5 11 46 + 11 = 57

According to the question,

N/2 = 57/2 = 28.5

cf greater than and nearest to 28.5 is 38.

So, median class = 10.5 - 15.5

Therefore, the upper limit of median class is 15.5.

Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!