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NCERT Exemplar Solutions Class 10 Mathematics Solutions for Statistics and Probability - Exercise 13.1 in Chapter 13 - Statistics and Probability

Question 1 Statistics and Probability - Exercise 13.1

Consider the following frequency distribution:

Class 1 - 5 6 - 10 11 - 15 16 - 20 21 - 25
Frequency 13 10 15 8 11

The upper limit of the median class is

Answer:

According to the question,

Classes are not continuous, hence, we make the data continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.

Class Frequency (f) Cumulative Frequency
0.5 - 5.5 13 13
5.5 - 10.5 10 13 + 10 = 23
10.5 - 15.5 15 23 + 15 = 38
15.5 - 20.5 8 38 + 8 = 46
20.5 - 25.5 11 46 + 11 = 57

According to the question,

N/2 = 57/2 = 28.5

cf greater than and nearest to 28.5 is 38.

So, median class = 10.5 - 15.5

Therefore, the upper limit of median class is 15.5.

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