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A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number

Answer:

**Solution:**

The mathematical term describing the possibility that something will happen is "probability. It is the capacity to comprehend and measure the likelihood of various combinations of outcomes.

Given A pair of dice is thrown

Required to find: Probability that the total of numbers on the dice is greater than 9

First let’s write the all possible events that can occur

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6),

It’s seen that the total number of events is 6^{2} = 36

Favourable events i.e. getting the total of numbers on the dice greater than 9 are

(5,5), (5,6), (6,4), (4,6), (6,5) and (6,6).

So, the total number of favourable events i.e. getting the total of numbers on the dice greater than 9 is 6

We know that, Probability = = Number of favourable outcomes/ Total number of outcomes

**Thus, the probability of getting the total of numbers on the dice greater than 9 = 6/36 = 1/6**

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