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A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, 1, 2, 3, …., 12 as shown in figure.

What is the probability that it will point to an odd number?

Answer:

**Solution:**

Events in probability are characterized as certain probable outcomes of an experiment that make up a subset of a finite sample space. Every event will always have a probability of occurrence between 0 and 1.

Given: A game of chance consists of spinning an arrow which is equally likely to come to rest pointing number 1, 2, 3 ….12

Required to find: Probability of following

Total numbers on the spin is 12

Favourable outcomes i.e. to get an odd number are 1, 3, 5, 7, 9, and 11

So, total number of favourable outcomes i.e. to get a prime number is 6

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

**Thus, the probability of getting a prime number = 6/12 = 1/2**

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