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A boy is flying a kite with a string of length 100 m. If the string is tight and the angle of elevation of the kite is 26^{0} 32’, find the height of the kite correct to one decimal place, (ignore the height of the boy).

Answer:

**Solution:**

A commonly used concept in relation to height and distance is the angle of elevation, particularly in trigonometry. It is described as a relationship between an oblique line from the observer's eye to an item above his eye and the horizontal plane.

Consider AB as the height of the kite A and AC as the string

Angle of elevation of the kite = 26^{0} 32’

Take AB = x m and AC = 100 m

We know that

sin θ = AB/AC

Substituting the values

sin 26^{0} 32’ = x/100

So we get

0.4467 = x/100

By further calculation

x = 100 × 0.4467

x = 44.67 = 44.7 m

**Hence, the height of the kite is 44.7 m.**

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