# ML Aggarwal Solutions Class 10 Mathematics Solutions for Heights and Distances Exercise 20 in Chapter 20 - Heights and Distances

Question 10 Heights and Distances Exercise 20

A boy is flying a kite with a string of length 100 m. If the string is tight and the angle of elevation of the kite is 260 32’, find the height of the kite correct to one decimal place, (ignore the height of the boy).

Solution:

A commonly used concept in relation to height and distance is the angle of elevation, particularly in trigonometry. It is described as a relationship between an oblique line from the observer's eye to an item above his eye and the horizontal plane.

Consider AB as the height of the kite A and AC as the string

Angle of elevation of the kite = 260 32’

Take AB = x m and AC = 100 m

We know that

sin θ = AB/AC

Substituting the values

sin 260 32’ = x/100

So we get

0.4467 = x/100

By further calculation

x = 100 × 0.4467

x = 44.67 = 44.7 m

Hence, the height of the kite is 44.7 m.

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