A man 1.8 m high stands at a distance of 3.6 m from a lamp post and casts a shadow of 5.4 m on the ground.
Find the height of the lamp post.
Solution:
The angle produced by the line of sight and the horizontal plane for an object above the horizontal is known as the angle of elevation. As seen in the image below, we must take into consideration two right angled triangles to get the height of the lamp post.
Consider
AB as the lamp post
CD is the height of man
BD is the distance of man from the foot of the lamp
FD is the shadow of man
Construct CE parallel to DB
Take AB = x and CD = 1.8 m
EB = CD = 1.8 m
AE = x – 1.8
Shadow FD = 5.4 m
In right △ AEC
tan θ = AE/CE
Substituting the values
tan θ = (x – 1.8)/ 3.6 …… (1)
In right △ CDF
tan θ = CD/FD
Substituting the values
tan θ = 1.8/5.4 = 1/3 ….. (2)
Using both the equations
(x – 1.8)/ 3.6 = 1/3
So we get
3x – 5.4 = 3.6
3x = 3.6 + 5.4 = 9.0
By division
x = 9/3 = 3.0
Hence, the height of lamp post is 3 m.
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