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ML Aggarwal Solutions Class 10 Mathematics Solutions for Trigonometric Identities Exercise 18 in Chapter 18 - Trigonometric Identities
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(sin 65o/ cos 25o) + (cos 32o/sin 58o) – sin 28o sec 62o + cosec2 30o
Answer:
Solution:
A pair of two angles that are complimentary are those whose sum is 90 degrees. So we can say that the complement of an angle θ is given by (90° - θ).
Given,
(sin 65o/ cos 25o) + (cos 32o/sin 58o) – sin 28o sec 62o + cosec2 30o
= (sin 65o/ cos (90o – 65o)) + (cos 32o/sin (90o – 32o)) – sin 28o sec (90o – 28o) + 22
= (sin 65o/sin 65o) + (cos 32o/cos 32o) – [sin 28o x cosec 28o] + 4
= 1 + 1 – 1 + 4
= 5
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