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ML Aggarwal Solutions Class 10 Mathematics Solutions for Trigonometric Identities Exercise 18 in Chapter 18 - Trigonometric Identities

Question 32 Trigonometric Identities Exercise 18

If sec θ + tan θ = m and sec θ – tan θ = n, prove that mn = 1.

Answer:

Solution:

First we can apply the algebraic identity (a+b) (a-b) = a2 -b2

Given,

sec θ + tan θ = m

sec θ – tan θ = n

Now,

mn = (sec θ + tan θ) (sec θ – tan θ)

= sec2 θ – tan2 θ = 1

Thus, mn = 1

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