If sec θ + tan θ = m and sec θ – tan θ = n, prove that mn = 1.
Solution:
First we can apply the algebraic identity (a+b) (a-b) = a2 -b2
Given,
sec θ + tan θ = m
sec θ – tan θ = n
Now,
mn = (sec θ + tan θ) (sec θ – tan θ)
= sec2 θ – tan2 θ = 1
Thus, mn = 1
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