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ML Aggarwal Solutions Class 10 Mathematics Solutions for Trigonometric Identities Exercise 18 in Chapter 18 - Trigonometric Identities
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Prove that following:
(cos (90o – θ) cos θ)/ tan θ + cos2 (90o – θ) = 1
Answer:
Solution:
Here we can apply the identity cos2 θ + sin2 θ =1.
L.H.S. = (cos (90o – θ) cos θ)/ tan θ + cos2 (90o – θ)
= (sin θ cos θ)/ tan θ + sin2 θ
= (sin θ cos θ)/ (sin θ/ cos θ) + sin2 θ
= cos2 θ + sin2 θ
= 1 = R.H.S.
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