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ML Aggarwal Solutions Class 10 Mathematics Solutions for Trigonometric Identities Exercise 18 in Chapter 18 - Trigonometric Identities
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Prove that following:
tan θ/ tan (90o – θ) + sin (90o – θ)/ cos θ = sec2 θ
Answer:
Solution:
Here we can apply the identity sec2 θ = 1+ tan2 θ , so
L.H.S = tan θ/ tan (90o – θ) + sin (90o – θ)/ cos θ
= tan θ/ cot θ + cos θ/ cos θ
= tan θ/ (1/tan θ) + 1
= tan2 θ + 1 = sec2 θ = R.H.S.
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