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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.5 in Chapter 17 - Mensuration

Question 21 Mensuration Exercise 17.5

The surface area of a solid metallic sphere is 1256 cm². It is melted and recast into solid right circular cones of radius 2.5 cm and height 8 cm.

Calculate the radius of the solid sphere. (Use π = 3.14).

Answer:

Solution:

The area that a sphere's outer surface covers in three dimensions is known as the surface area of the object. A sphere is a three-dimensional solid that resembles a circle in shape and is round. Surface area = 4 π r2 square units is the formula for a sphere's total surface area expressed in terms of π .

Given surface area of the solid metallic sphere = 1256 cm2

4π R2 = 1256

4×3.14×R2 = 1256

R2 = 1256/4×3.14

R2 = 100

R = 10

Hence the radius of solid sphere is 10 cm. M L Aggarwal - Understanding ICSE Mathematics - Class 10 chapter Mensuration Question 21 Solution image

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