- GST
- Banking
- Shares and Dividends
- Quadratic Equations in One Variable
- Factorization
- Ratio and Proportion
- Matrices
- Arithmetic and Geometric Progression
- Reflection
- Section Formula
- Equation of Straight Line
- Similarity
- Locus
- Circles
- Constructions
- Mensuration
- Trigonometric Identities
- Trigonometric Tables
- Heights and Distances
ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.4 in Chapter 17 - Mensuration
Prev
A cone of maximum volume is curved out of a block of wood of size 20 cm x 10 cm x 10 cm. Find the volume of the remaining wood.
Solution:
Volume of the remaining wood can be calculated using the difference between the volume of cuboidal block of wood and volume of cone.
Given dimensions of the block of wood = 20 cm × 10 cm× 10 cm
Volume of the block of wood = 20×10×10 = 2000 cm3 [Volume = lbh]
Diameter of the cone, d = 10 cm
Radius of the cone , r = d/2 = 10/2 = 5 cm
Height of the cone, h = 20 cm
Volume of the cone = (1/3)π r2h
= (1/3)×(22/7)×52×20
= (22×25×20)/(3×7)
= 11000/21 cm3
Volume of the remaining wood = Volume of block of wood – Volume of cone
= 2000-11000/21
= (21×2000-11000)/21
= (42000-11000)/21
= 31000/21
= 1476.19 cm3
Hence the volume of the remaining wood is 1476.19 cm3.
Facebook
Whatsapp
Copy Link
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
