ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.3 in Chapter 17 - Mensuration

Question 11 Mensuration Exercise 17.3

The radius of a spherical balloon increases from 7 cm to 14 cm as air is jumped into it. Find the ratio of the surface areas of the balloon in two cases.



The curved surface area is equal to the whole area of the sphere since the sphere is completely curved.

Given radius of the spherical balloon, r = 7 cm

Radius of the spherical balloon after air is pumped, R = 14 cm

Surface area of the sphere = 4π r2

Ratio of surface areas of the balloons =

4π r2/4π R2

= r2/R2

= 72/142

= 1/4

Hence the ratio of the surface areas of the spheres is 1:4. M L Aggarwal - Understanding ICSE Mathematics - Class 10 chapter Mensuration Question 11 Solution image

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