# ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.3 in Chapter 17 - Mensuration

Question 11 Mensuration Exercise 17.3

The radius of a spherical balloon increases from 7 cm to 14 cm as air is jumped into it. Find the ratio of the surface areas of the balloon in two cases.

Solution:

The curved surface area is equal to the whole area of the sphere since the sphere is completely curved.

Given radius of the spherical balloon, r = 7 cm

Radius of the spherical balloon after air is pumped, R = 14 cm

Surface area of the sphere = 4π r2

Ratio of surface areas of the balloons =

4π r2/4π R2

= r2/R2

= 72/142

= 1/4

Hence the ratio of the surface areas of the spheres is 1:4.

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