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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.3 in Chapter 17 - Mensuration
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If the volume of a sphere is 179\frac{2}{3} , Finds its radius and surface area.
Answer:
Solution:
The area that a sphere's outer surface covers in three dimensions is known as the surface area of the object. A sphere is a three-dimensional solid that resembles a circle in shape.
Given volume of the sphere is 179\frac{2}{3}
(4/3)π r3 =** 179\frac{2}{3} **= 539/3**
(4/3)×(22/7)×r3 = 539/3
r3 = (539×3×7)/(4×22×3)
r3 = 49×7/8
r3 = 7×7×7/(2×2×2)
Taking cube root on both sides, we get
r = 7/2 = 3.5 cm
Surface area of the sphere = 4π r2
= 4×(22/7)×(7/2)2
= 22×7
= 154 cm2
Hence the radius and the surface area of the sphere is 3.5 cm and 154 cm2 respectively. 
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