chapter-header

ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.2 in Chapter 17 - Mensuration

Question 27 Mensuration Exercise 17.2

A semi-circular lamina of radius 35 cm is folded so that the two bounding radii are joined together to form a cone.

Find the radius of the cone.

Answer:

Solution:

The shape of a cone is produced by stacking several triangles and spinning them around an axis.

M L Aggarwal - Understanding ICSE Mathematics - Class 10 chapter Mensuration Question 27 Solution image

Given radius of the semi circular lamina, r = 35 cm

A cone is formed by folding it.

So the slant height of the cone, l = 35 cm

Let r1 be radius of cone.

Semicircular perimeter of lamina becomes the base of the cone.

r = 2r1

r = 2 r1

35 = 2 r1

r1 = 35/2= 17.5 cm

Hence the radius of the cone is 17.5 cm.

Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved