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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.2 in Chapter 17 - Mensuration
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A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the cone so formed. (Take π = 3.14)
Solution:
The shape of a cone is produced by stacking several triangles and spinning them around an axis. It has a total surface area and a curved surface area because it has a flat base.
The triangle is rotated about the side 8cm.
So the height of the resulting cone, h = 8 cm
Radius, r = 6 cm
Slant height, l =10 cm
Volume of the cone, V = (1/3)r2h
V = (1/3)×3.14×62×8
V = (1/3)×3.14×36×8
V = 3.14×12×8
V = 301.44 cm3
Hence the volume of the cone is 301.44 cm3.
Curved surface area of the cone = π rl
= 3.14×6×10
= 188.4
Hence the curved surface area of the cone is 188.4 cm2.
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