# ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.2 in Chapter 17 - Mensuration

Question 24 Mensuration Exercise 17.2

The volume of a right circular cone is 9856 cm3  and the area of its base is 616 cm2 .

Find total surface area of the cone.

Solution:

The total area occupied by the cone in three dimensions is referred to as the cone's total surface area. It is equal to the total of the cone's base and curved surface.

Given base area of the cone = 616 cm2

π r2 = 616

(22/7)×r2 = 616

r2 = 616×7/22

r2 = 196

r = 14

Given volume of the cone = 9856 cm3

(1/3)π r2h = 9856

(1/3)×(22/7)×142 ×h = 9856

h = (9856×3×7)/(22×142)

h = (9856×3×7)/(22×196)

h = 48

Total surface area of the cone = π r(l+r)

= (22/7)×14×(50+14)

= 22×2×64

= 2816 cm2

Hence the total surface area of the cone is 2816 cm2.

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