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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.2 in Chapter 17 - Mensuration
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The volume of a right circular cone is 9856 cm3 and the area of its base is 616 cm2 .
Find the slant height of the cone.
Answer:
Solution:
Assume that a cone has a height of "h" and a circular base with radius "r." This cone will have a volume that is one-third of the product of the base's area and its height.
Given base area of the cone = 616 cm2
π r2 = 616
(22/7)×r2 = 616
r2 = 616×7/22
r2 = 196
r = 14
Given volume of the cone = 9856 cm3
(1/3)π r2h = 9856
(1/3)×(22/7)×142 ×h = 9856
h = (9856×3×7)/(22×142)
h = (9856×3×7)/(22×196)
h = 48
Slant height, l = √(h2+r2)
l = √(482+142)
l = √(2304+196)
l = √(2500
l = 50
Hence the slant height of the cone is 50 cm. 
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