Jump to
- GST
- Banking
- Shares and Dividends
- Quadratic Equations in One Variable
- Factorization
- Ratio and Proportion
- Matrices
- Arithmetic and Geometric Progression
- Reflection
- Section Formula
- Equation of Straight Line
- Similarity
- Locus
- Circles
- Constructions
- Mensuration
- Trigonometric Identities
- Trigonometric Tables
- Heights and Distances
ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.2 in Chapter 17 - Mensuration
Prev
A Jocker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the cloth required to make 10 such caps.
Answer:
Solution:
The shape of a cone is produced by stacking several triangles and spinning them around an axis. It has a total surface area and a curved surface area because it has a flat base.
Given height of the cone, h _=_ 24 cm
Radius, r = 7 cm
We know that l2 = h2+r2
l2 = 242+72
l2 = 576+49
l2 = 625
l = √625
l = 25
Curved surface area = π rl
= (22/7)×7×25
= 22×25
= 550 cm2
So the area of the cloth required to make 10 such caps = 10×550 = 5500
Hence the area of the cloth required to make 10 caps is 5500 cm2. 
Related Questions
Facebook
Whatsapp
Copy Link
Exercises
Chapters
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved