If the inner curved surface of the well in part (i) above is to be plastered at the rate of Rs 50 per m2, find the cost of plastering.
Solution:
The area of any given cylinder's curved surface with a base radius of "r" and a height of "h" is referred to as the "curved surface area of a cylinder" (CSA)
Curved surface area of the well = 2π rh
= 2×(22/7)×1×20
= 880/7 m2
Cost of plastering the well per m2 = Rs. 50
Total cost of plastering the well = 50×(880/7)
= Rs. 6285.71
Hence the total cost of plastering is Rs. 6285.71.
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