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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.1 in Chapter 17 - Mensuration

Question 9 Mensuration Exercise 17.1

If the inner curved surface of the well in part (i) above is to be plastered at the rate of Rs 50 per m2, find the cost of plastering.

Answer:

Solution:

The area of any given cylinder's curved surface with a base radius of "r" and a height of "h" is referred to as the "curved surface area of a cylinder" (CSA)

Curved surface area of the well = 2π rh

= 2×(22/7)×1×20

= 880/7 m2

Cost of plastering the well per m2 = Rs. 50

Total cost of plastering the well = 50×(880/7)

= Rs. 6285.71

Hence the total cost of plastering is Rs. 6285.71. M L Aggarwal - Understanding ICSE Mathematics - Class 10 chapter Mensuration Question 9 Solution image

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