 # ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.1 in Chapter 17 - Mensuration

The given figure shows a metal pipe 77 cm long. The inner diameter of a cross-section is 4 cm and the outer one is 4.4 cm.

Find its total surface area. Solution:

The amount of space that is covered by the curved surface and flat surface of a cylinder's bases is known as the cylinder's surface area.

Given height of the metal pipe = 77 cm

Inner diameter = 4 cm

Inner radius, r = d/2 = 4/2 = 2 cm

Outer diameter = 4.4 cm

Outer radius, R = d/2 = 4.4/2 = 2.2 cm

Area of ring = (R2-r2)

= (22/7)×(2.22-22)

= (22/7)×(4.84-4)

= (22/7)×0.84

= 2.64

Total surface area = inner surface area + outer surface area + area of two rings

= 968+ 1064.8+ 2×2.64

= 2038.08 cm2

Hence the total surface area of the metal pipe is 2038.08 cm2. Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!