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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.1 in Chapter 17 - Mensuration

Question 24 Mensuration Exercise 17.1

The given figure shows a metal pipe 77 cm long. The inner diameter of a cross-section is 4 cm and the outer one is 4.4 cm.

Find its outer curved surface area

Question 24 Image - M L Aggarwal - Understanding ICSE Mathematics - Class 10 chapter Mensuration

Answer:

Solution:

In cylinder, ther are two types of curved surface area. One is inner surface area and the other one is outer surface area.

Given height of the metal pipe = 77 cm

Inner diameter = 4 cm

Inner radius, r = d/2 = 4/2 = 2 cm

Outer diameter = 4.4 cm

Outer radius, R = d/2 = 4.4/2 = 2.2 cm

Outer curved surface area = 2π Rh

= 2×(22/7)×2.2×77

= 1064.8 cm2

Hence the outer curved surface area is 1064.8 cm2. M L Aggarwal - Understanding ICSE Mathematics - Class 10 chapter Mensuration Question 24 Solution image

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