# ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.1 in Chapter 17 - Mensuration

Question 23 Mensuration Exercise 17.1

The given figure shows a metal pipe 77 cm long. The inner diameter of a cross-section is 4 cm and the outer one is 4.4 cm.

Find its inner curved surface area

Solution:

The space that is covered by the curved surface of a cylinder and the flat surface of its bases is known as the surface area of a cylinder.

Given height of the metal pipe = 77 cm

Inner diameter = 4 cm

Inner radius, r = d/2 = 4/2 = 2 cm

Outer diameter = 4.4 cm

Outer radius, R = d/2 = 4.4/2 = 2.2 cm

Inner curved surface area = 2π rh

= 2×(22/7)×2×77

= 968 cm2

Hence the inner surface area is 968 cm2.

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