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ML Aggarwal Solutions Class 10 Mathematics Solutions for Mensuration Exercise 17.1 in Chapter 17 - Mensuration
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A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.
Answer:
Solution:
The density of a cylinder is determined by its volume, which represents how much material may be immersed in it or carried inside of it.
Given internal diameter of the tube = 11.2 cm
Internal radius, r = d/2 = 11.2/2 = 5.6 cm
Length of the tube, h = 21 cm
Thickness = 0.4 cm
Outer radius, R= 5.6+0.4 = 6 cm
Volume of the metal = π R2h- π r2h
= π h(R2-r2)
= (22/7)×21×(62-5.62)
= 66×(6+5.6)(6-5.6)
= 66×11.6×0.4
= 306.24 cm3
Hence the volume of the metal is 306.24 cm3. 
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