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ML Aggarwal Solutions Class 10 Mathematics Solutions for Similarity Exercise 13.3 in Chapter 13 - Similarity

Question 5 Similarity Exercise 13.3

∆ABC ~ ∆DEF. If BC = 3 cm, EF = 4 cm and area of ∆ABC = 54 sq. cm. Determine the area of ∆DEF.

Answer:

Solution:-

The square of any ratio between any two corresponding sides of two similar triangles is equal to the ratio of their areas.

From the question it is given that,

∆ABC ~ ∆DEF

BC = 3 cm, EF = 4 cm

Area of ∆ABC = 54 sq. cm.

We know that,

Area of ∆ABC/ area of ∆DEF = BC2/EF2

54/area of ∆DEF = 32/42

54/area of ∆DEF = 9/16

By cross multiplication we get,

Area of ∆DEF = (54 × 16)/9

= 6 × 16

= 96 cm2

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