∆ABC ~ DEF. If area of ∆ABC = 9 sq. cm., area of ∆DEF =16 sq. cm and BC = 2.1 cm., find the length of EF.
Solution:-
The square of any ratio between any two corresponding sides of two similar triangles is equal to the ratio of their areas.
From the question it is given that,
∆ABC ~ DEF
Area of ∆ABC = 9 sq. cm
Area of ∆DEF =16 sq. cm
We know that,
area of ∆ABC/area of ∆DEF = BC2/EF2
area of ∆ABC/area of ∆DEF = BC2/EF2
9/16 = BC2/EF2
9/16 = (2.1)2/x2
2.1/x = √9/√16
2.1/x = ¾
By cross multiplication we get,
2.1 × 4 = 3 × x
8.4 = 3x
x = 8.4/3
x = 2.8
Therefore, EF = 2.8 cm
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