 # ML Aggarwal Solutions Class 10 Mathematics Solutions for Similarity Exercise 13.1 in Chapter 13 - Similarity

A 15 metres high tower casts a shadow of 24 metres long at a certain time and at the same time, a telephone pole casts a shadow 16 metres long.

Find the height of the telephone pole.

Solution:-

If two triangles are similar, than the ratio of their corresponding sides are proportional.

From the question it is given that,

Height of a tower PQ = 15m

It’s shadow QR = 24 m

Let us assume the height of a telephone pole MN = x

It’s shadow NO = 16 m Given, at the same time,

∆PQR ~ ∆MNO

Therefore, PQ/MN = ON/RQ

15/x = 24/16

By cross multiplication we get,

x = (15 × 16)/24

x = 240/24

x = 10

Therefore, height of pole = 10 m.

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