Selina Solutions Class 9 Mathematics Solutions for Exercise 9(B) in Chapter 9 - Chapter 9- Triangles [Congruency in Triangles]

Question 18 Exercise 9(B)

Question 18 Image - Selina Solutions CONCISE Maths - Class 9 ICSE chapter Chapter 9- Triangles [Congruency in Triangles]

Answer:

Solution

Selina Solutions CONCISE Maths - Class 9 ICSE chapter Chapter 9- Triangles [Congruency in Triangles] Question 18 Solution image

Video transcript

"hello students my name is pramit singh and i welcome you all to leader learning homework one of india's best online classes now today in this video we have a question that is based on congruent triangles the question says a d and b c are equal perpendicular to a line segment a b now you can see we have made a line segment a b this is line segment a b and a d this side and bc they are equal that is given already if a d and b c are on different sides if a d and b c are on different sides of a b where is a b this is a b a d and bc are on different side but you can check we have triangle point o common both of them then we have to prove c d bisects a b by a c d c d bisects a b so that means if it bisects so we have to prove what o as the midpoint of a b so let us take two triangles you can see we have already solved the question and triangle aod aod and triangle boc angle aod this angle will be equal to this vertically opposite angle already given so we have first angle angle dao this and angle obc or cbo 90 degree that is also second angle now ad is equal to bc that is already given so based on this aas criterion we have triangle aod congruent to triangle boc now based on that ao becomes equal to ob so that if ao is equal to ob so that means o is midpoint of a b hence we have proof so if it is midpoint so that means cd bisects a b c d bisects a b so i hope you have understood the concept very clearly but still if you have any doubt do comment in the comment box and please like and subscribe our channel follow thank you"

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