In a triangle, ABC, AB=BC, AD is perpendicular to side BC and CE is
perpendicular to side AB. Prove that:
AD=CE.
Answer:
Solution
Video transcript
"hello students my name is rabbit singh
and i welcome you all to leader learning
homework
one of india's best online classes now
today in this video we have a question
that is based on the topic
congruent triangles the question says in
a triangle abc
ab is equal to bc now you can check this
is a b
and it is equal to bc that is given and
a d
is perpendicular to side bc now you can
see we have drawn
a d and that is perpendicular that means
90 degree
and ce is perpendicular to a b this is c
e
and it is perpendicular to side a b what
we have to prove prove that
a d that is this side
is equal to c basically we have to prove
the perpendicular to be equal now
if you check we will be using the
congruent triangle conditions in
triangle abd
whereas abd a b d
and triangle c b e so let us mark that
with different colors
a b
d this triangle
and second one is c b e
c b e
this triangle a b is equal to bc that is
already given
so that is side now angle adb
angle a d b this angle
and angle c e b angle c e b 90 degree
that is
because altitude
and second last part you can check angle
b is common
this is angle b this is common to both
of them so this is common
now this becomes angle
and the last one becomes angle now we
have side angle side congruent
triangle so angle triangle abd becomes
congruent to triangle cbe
we have proved that now based on this we
will prove
a d is equal to c e
y according to cpct corresponding parts
of congruent triangle so i hope you have
understood the concept very clearly
but still if you have any doubt do
comment in the comment box and please i
can subscribe our channel for lido thank
you
"