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If AP bisects angle BAC and M is any point on AP, prove that the

perpendiculars drawn from M to Ab and AC are equal.

Answer:

Solution

"hello students my name is pramit singh
and i welcome you all
to lido learning homework one of india's
best online classes
now today in this video we have a
question that is based on the topic
lines and angles the question says if ap
bisects angle bac
you can see this is ap it bisects angle
b a c that means this angle will be
equal to this angle
so m is any point on ap so this is m any
point on eb
prove that the perpendicular runs from n
m to a p
a b this is a b so this is the
perpendicular that is l
that means this is 90 degree and n
that means this is also 90 degree so we
have to prove they are equal
this and this are equal very simple
question
you will take two triangles a l m and a
n m such that angle l a m this and this
are equal y because ap is the
perpendicular bisector
angle a and m and angle alm are 90
degree
because 90 degree it is given
and for the last one we have
am is equal to am because it is common
side so based on
a a s criterion triangle alm
is congruent to triangle a n m so based
on that
ml is equal to m n y c p c t
corresponding parts of congruent
triangles so hence proved i hope you
have understood the concept very clearly
but still if you have any doubt do
comment in the comment box and please
like and subscribe our channel follow
thank you"

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