# Selina Solutions Class 9 Mathematics Solutions for Exercise 9(A) in Chapter 9 - Chapter 9- Triangles [Congruency in Triangles]

Question 13 Exercise 9(A)

In the following figure, AB=AC and AD is perpendicular to BC. BE bisects angle

B and EF is perpendicular to AB.

Prove that:

(i) BD=CD

(ii) ED=EF

Solution

Video transcript
"hello students my name is rabbit singh and i welcome you all to leader learning homework one of india's best online classes now today in this video we have a question that is based on the topic triangles the question says in the following figure a b is equal to ac you can see this is a b and this is ac they are equal and a d is perpendicular to b c a d is perpendicular to b c b e bisects angle b this is a line this bisects angle b so that means they are equal and ef is perpendicular to a b now prove that e d is equal to e f t d means this is equal to this that we have to prove now consider triangle efb and edb e f b and e d b so angle efb and angle e db both are 90 degree and e b is equal to e b common why because it is angle bisector this line and angle f b d angle f b d f b d and angle d b e that is given angle d b e f b d equals to dv e they are equal that is given so based on that triangle efb is congruent to triangle adp now if they are congruent but how they are congruent asa theorem a angle side angle criterion so based on that ed that means this part is equal to ef cpct corresponding part of congruent triangles so i hope you have understood the concept very clearly but still if you have any doubt do comment in the comment box and please like and subscribe our channel for lido thank you"
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