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In the following figure, AB=AC and AD is perpendicular to BC. BE bisects angle

B and EF is perpendicular to AB.

Prove that:

(i) BD=CD

(ii) ED=EF

Answer:

Solution

"hello students my name is rabbit singh
and i welcome you all
to leader learning homework one of
india's best online classes
now today in this video we have a
question that is based on the topic
triangles the question says in the
following figure
a b is equal to ac you can see this is a
b
and this is ac they are equal and a d is
perpendicular to b c
a d is perpendicular to b c b e bisects
angle b
this is a line this bisects angle b so
that means they are equal and ef is
perpendicular to
a b now prove that e d is equal to e f t
d means
this is equal to this that we have to
prove now consider triangle efb
and edb e f b and e d
b so angle efb and angle e db both are
90 degree
and e b is equal to e b common why
because it is angle bisector
this line and angle f b d angle f
b d f b d and angle
d b e that is given angle
d b e f b
d equals to dv e they are equal that is
given
so based on that triangle efb is
congruent to triangle adp
now if they are congruent but how they
are congruent asa theorem
a angle side angle criterion so based on
that ed
that means this part is equal to ef
cpct corresponding part of congruent
triangles so i hope you have understood
the concept very clearly but still if
you have any doubt
do comment in the comment box and please
like and subscribe our channel for lido
thank you"

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