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\text { If } a^{2}+b^{2}=34 \text { and } a b=12 ; \text { find: }

(i)(a+b)^{2}+5(a-b)^{2}

(ii)(a+b)^{2}+5(a-b)^{2}

Answer:

a² + b² = 34, ab= 12

(a + b)² = a² + b² + 2ab

= 34 + 2 x 12 = 34 + 24 = 58

(a - b)² = a² + b² - 2ab

= 34 - 2 x 12 = 34- 24 = 10

(i) 3(a + b)² + 5(a - b)²

= 3 x 58 + 5 x 10 = 174 + 50

= 224

(ii) 7(a - b)² - 2(a + b)²

= 7 x 10 - 2 x 58 = 70 - 116 = -46

"hello students welcome to leader
learning question answer video solution
today's problem is if a square plus b
square is 34 and a b is 12
we need to find the value of this
problem my name is pulsha uh
by the way so let's get started
so we needs to find the value of
3 a plus b whole square
plus 5 a minus b whole square
so guys get ready with your identities
because we're going to use
lots of identities so let's get started
a plus b square can be written as a
square
plus b square plus twice of a b
similarly a minus b can be written as a
square
plus b square minus off
to a b now let's start
substituting the values because you
should know that
a square plus b square is 34 and a b is
12. so a square plus b square is 34.
plus a b is 12
bracket close similarly a square plus b
square is 34 minus
of 2 times 12.
now these are the values now start
simplifying guys
now 34 minus
12 times 2 is 24.
similarly 34
minus 24
now that's the simplified version of the
problem
now let's keep on solving it now 34
plus 24 will be 58
and 34 minus 24
would be 10.
58 times 3
would be 174
and 5 times 10 is
50. so 174
plus 50 will give us 224
as an answer thank you so much
for watching the video kids please keep
it in mind
that we needs to make sure that we
remember our identities
without identities it would be a little
little typical job
but i hope you can do it thank you so
much for watching the video kids
have a wonderful day for more fun videos
subscribe to leader
god bless you"

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