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- Chapter 1- Rational and Irrational Numbers
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- Chapter 3- Compound Interest [Using Formula
- Chapter 4- Expansions
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- Chapter 6- Simultaneous Equations
- Chapter 7- Indices [exponents]
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Question 9 Exercise 21(A)

A hollow square-shaped tube open at both ends is made of iron. The internal square is 5 cm side and the length of the tube is 8 cm. There are 192 cm3 of iron in this tube. Find its thickness.

Answer:

Given that the volume of the iron in the tube 192 cm3

Let the thickness of the tube = x cm

Side of the external square = (5 + 2x) cm

The external volume of the tube - its internal volume= volume of iron in the tube

According to the question,

Then, the thickness is 1 cm.

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