A hollow square-shaped tube open at both ends is made of iron. The internal square is 5 cm side and the length of the tube is 8 cm. There are 192 cm3 of iron in this tube. Find its thickness.
Given that the volume of the iron in the tube 192 cm3
Let the thickness of the tube = x cm
Side of the external square = (5 + 2x) cm
The external volume of the tube - its internal volume= volume of iron in the tube
According to the question,
Then, the thickness is 1 cm.
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