- Chapter 1- Rational and Irrational Numbers
- Chapter 2- Compound Interest [Without Using Formula
- Chapter 3- Compound Interest [Using Formula
- Chapter 4- Expansions
- Chapter 5- Factorisation
- Chapter 6- Simultaneous Equations
- Chapter 7- Indices [exponents]
- Chapter 8- Logarithms
- Chapter 9- Triangles [Congruency in Triangles]
- Chapter 10- Isosceles Triangle
- Chapter 11- Inequalities
- Chapter 12- Mid-Point and Its Converse
- Chapter 13- Pythagoras Theorem
- Chapter 14- Rectilinear Figures
- Chapter 15- Construction of Polygons
- Chapter 16- Area Theorems
- Chapter 17- Circles
- Chapter 18- Statistics
- Chapter 19- Mean and Median
- Chapter 20- Area and Perimeter of Plane Figures
- Chapter 21- Solids
- Chapter 22- Trigonometrical Ratios
- Chapter 23- Trigonometrical Ratios of Standard Angles
- Chapter 24- Solution Of Right Triangles
- Chapter 25- Complementary angles
- Chapter 26- Co-ordinate Geometry
- Chapter 27- Graphical Solution
- Chapter 28- Distance Formula
Selina Solutions Class 9 Mathematics Solutions for Exercise 2(B) in Chapter 2 - Chapter 2- Compound Interest [Without Using Formula
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A man lends ₹ 12,500 at 12% for the first year, at 15% for the second year and at 18% for the third year. If the rates of interest are compounded yearly; find the difference between C.I of the first year and the compound interest for the third year.
For 1st year
P = Rs. 12500
R = 12%
R = 1 year
I=\frac{12500 \times 12 \times 1}{100}=R s, 1500
A = 12500 + 1500 = Rs. 14000
For 2nd year
P = Rs. 1400
R = 15%
T = 1 year
I=\frac{14000 \times 15 \times 1}{100}=R s, 2898I=\frac{14000 \times 15 \times 1}{100}=R s. 2898
A = 1400 + 2100 = Rs. 16100
For 3rd year
P = Rs. 16100
R = 18%
T = 1 year
I=\frac{16100 \times 18 \times 1}{100}=R s .2898
A = 16100 + 2898 = Rs. 3998
Difference between the compound interest of the third year and first year
= Rs. 2893 - Rs. 1500
= Rs. 1398
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