Draw a line segment of length βπ cm.
We know that, \sqrt{8}=\sqrt{3^{2}-1^{2}}
Which relates to: Hypotenuse= \sqrt{\operatorname{side} 1^{2}+\operatorname{side} 2^{2}}[\text { Pythagoras theorem }]
HypotenuseΒ²-Side1Β² = Side2Β²
Hence, Considering Hypotenuse =3cm and Side 1 =1 cm,
We get a right angled triangle OAB such that:
β A=90Β°, OB=3cm and AB=1cm
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