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Selina solutions

Grade 7

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Question 10

Q10) Kumar bought a transistor for Rs. 960. He paid 12\frac{1}{2}

% cash money. The rest he agreed to pay in 12 equal monthly installments. How much will he pay each month?

Solution:

Price of transistor = Rs. 960

Amount paid in cash = 12\frac{1}{2}\%\ ofRs.960=\frac{25}{2\times100}\times960=Rs.120

Balance amount = Rs. 960 - Rs. 120 = Rs. 840

No. of installments = 12

∴ Amount of each instalments = 840\div12=Rs.70

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