Selina solutions

Selina solutions

Grade 7

Percent and Percentage | Exercise 8(A)

Question 11

Q11) Express :

(i) 3\frac{2}{5} as a percent

(ii) 0.0075 as percent

(iii) 3 : 20 as percent

(iv) 60 cm as percent of 1 m 25 cm

(v) 9 hours as a percent of 4 days.

Solution:

(i) 3\frac{2}{5} as a percent

3\frac{2}{5}=\frac{3\times5+2}{5}=\frac{17}{5}

Now convert \frac{17}{5} as a percent = \frac{17}{5}\times100=340\%

(ii) 0.0075 as percent

0.0075 x 100 = 0.75%

Or \frac{0.0075}{10000}\times100=0.75\%

(iii) 3:20 as percent = \frac{3}{20}\times100=15\%

(iv) 60cm as percent of 1m 25 cm

60 cm as percent of ( 1 x 100 + 25) cm

∵ 1 metre = 100 cm = \frac{60}{125}\times100=12\times4=48\%

(v) 9 hours as a percent of 4 days = 1 days = 24 hours

∴ 4 hours = 4 x 24 = 96 hours = \frac{9}{96}\times100=\frac{75}{8}\%\ or\ 9\frac{3}{8}\%

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Question 11

Q11) Express :

(i) 3\frac{2}{5} as a percent

(ii) 0.0075 as percent

(iii) 3 : 20 as percent

(iv) 60 cm as percent of 1 m 25 cm

(v) 9 hours as a percent of 4 days.

Solution:

(i) 3\frac{2}{5} as a percent

3\frac{2}{5}=\frac{3\times5+2}{5}=\frac{17}{5}

Now convert \frac{17}{5} as a percent = \frac{17}{5}\times100=340\%

(ii) 0.0075 as percent

0.0075 x 100 = 0.75%

Or \frac{0.0075}{10000}\times100=0.75\%

(iii) 3:20 as percent = \frac{3}{20}\times100=15\%

(iv) 60cm as percent of 1m 25 cm

60 cm as percent of ( 1 x 100 + 25) cm

∵ 1 metre = 100 cm = \frac{60}{125}\times100=12\times4=48\%

(v) 9 hours as a percent of 4 days = 1 days = 24 hours

∴ 4 hours = 4 x 24 = 96 hours = \frac{9}{96}\times100=\frac{75}{8}\%\ or\ 9\frac{3}{8}\%

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