Selina solutions

# Question 1

(i) \frac{7}{5}and\ \frac{2}{5}

(ii) \frac{-4}{9}and\ \frac{2}{9}

(iii) \frac{5}{-12}and\ \frac{1}{12}

(iv) \frac{4}{-15}and\ \frac{-7}{-15}

(v) \frac{-7}{25}and\ \frac{9}{-25}

(vi) \frac{-7}{26}and\ \frac{7}{-26}

Solution 1:

(i) \frac{7}{5}and\ \frac{2}{5}

= \frac{7}{5}+\frac{2}{5}=\ \frac{7+2}{5}=\frac{9}{5}

(ii) \frac{-4}{9}and\ \frac{2}{9}

= \frac{-4}{9}+\frac{2}{9}=\ \frac{-4+2}{9}=\frac{-2}{9}

(iii) \frac{5}{-12}and\ \frac{1}{12}

=

\frac{-5}{12}+\frac{1}{12}=\frac{-5+1}{12}=\frac{-4}{12}

(iv) \frac{4}{-15}and\ \frac{-7}{-15}

= \frac{-4}{15}+\frac{7}{15}=\frac{-4+7}{15}=\frac{3}{15}

(v) \frac{-7}{25}and\ \frac{9}{-25}

= \frac{-7}{25}+\frac{-9}{25}=\frac{-7+\left(-9\right)}{25}=\frac{-7-9}{25}=\frac{-16}{25}

(vi) \frac{-7}{26}and\ \frac{7}{-26}

\frac{-7}{26}+\frac{-7}{26}=\frac{-7+\left(-7\right)}{26}=\frac{-7-7}{26}=\frac{-14}{26}

Want to top your mathematics exam ?

Learn from an expert tutor.

Lido

Courses

Race To Space

Teachers

Syllabus

Maths | ICSE Maths | CBSE
Science | ICSE Science | CBSE
English | ICSE English | CBSE

Terms & Policies

NCERT Syllabus

Maths
Science

Selina Syllabus

Maths
Physics
Biology

Allied Syllabus

Chemistry