Selina solutions

Selina solutions

Grade 7

Set Concepts (Some Simple Divisions by Vedic Method) | Exercise 13(B)

Question 1

Q1) Write the cardinal number of each of the following sets:

(i) A = Set of days in a leap year.

(ii) B = Set of numbers on a clock-face.

(iii) C = {x : x ∈ N and x ≤ 7}

(iv) D = Set of letters in the word “PANIPAT”.

(v) E = Set of prime numbers between 5 and 15.

(vi) F = {x : x ∈ Z and – 2 < x ≤ 5}

(vii) G = {x : x is a perfect square number, x ∈N and x ≤ 30}.

Solution:

(i) The number of days in leap year is 366.

∴ n A = 366

(ii) The number on clock face is 12.

∴ n B = 12

(iii) The total number of set is 7.

∴ n C = 7

(iv) The number of letters in PANIPAT is 5.

∴ n D = 5

(v) The number of prime number between 5 and 13 is 3.

∴ n E = 3

(vi) The total numbers between -2 and 7 is 7.

∴ n F = 7

(vii) There are 5 perfect square numbers less thn 30.

∴ n G = 5

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subject-cta

Question 1

Q1) Write the cardinal number of each of the following sets:

(i) A = Set of days in a leap year.

(ii) B = Set of numbers on a clock-face.

(iii) C = {x : x ∈ N and x ≤ 7}

(iv) D = Set of letters in the word “PANIPAT”.

(v) E = Set of prime numbers between 5 and 15.

(vi) F = {x : x ∈ Z and – 2 < x ≤ 5}

(vii) G = {x : x is a perfect square number, x ∈N and x ≤ 30}.

Solution:

(i) The number of days in leap year is 366.

∴ n A = 366

(ii) The number on clock face is 12.

∴ n B = 12

(iii) The total number of set is 7.

∴ n C = 7

(iv) The number of letters in PANIPAT is 5.

∴ n D = 5

(v) The number of prime number between 5 and 13 is 3.

∴ n E = 3

(vi) The total numbers between -2 and 7 is 7.

∴ n F = 7

(vii) There are 5 perfect square numbers less thn 30.

∴ n G = 5

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