Selina solutions

Selina solutions

Grade 6

Playing with Numbers | Exercise 9(C)

Question 12

Q12)In each of the following numbers replace M by the smallest number to make resulting number divisible by 9.

(i) 76 M 91

(ii) 77548 M

(iii) 627 M 9

Solution :

(i) 76 M 91

The given number = 76 M 91

For a number to be divisible by 9 sum of its digits must be divisible by 9.

Sum of its given digits = 7 + 6 + 9 + 1 = 23

The number next to 23, which is divisible by 9 is 27

Required smallest number = 27 - 23 = 4

Therefore , value of M is 4.

(ii) 77548 M

The given number = 77548 M

For a number to be divisible by 9 sum of its digits must be divisible by 9.

Sum of its given digits = 7 + 7 + 5 + 4 + 8 = 31

The number next to 31, which is divisible by 9 is 36

Required smallest number = 36 - 31 = 5

Therefore , value of M is 5.

(iii) 627 M 9

The given number = 627 M 9

For a number to be divisible by 9 sum of its digits must be divisible by 9.

Sum of its given digits = 6 + 7 + 2 + 9 = 24

The number next to 24, which is divisible by 9 is 27

Required smallest number = 27 - 24 = 3

Therefore , value of M is 3.

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subject-cta

Question 12

Q12)In each of the following numbers replace M by the smallest number to make resulting number divisible by 9.

(i) 76 M 91

(ii) 77548 M

(iii) 627 M 9

Solution :

(i) 76 M 91

The given number = 76 M 91

For a number to be divisible by 9 sum of its digits must be divisible by 9.

Sum of its given digits = 7 + 6 + 9 + 1 = 23

The number next to 23, which is divisible by 9 is 27

Required smallest number = 27 - 23 = 4

Therefore , value of M is 4.

(ii) 77548 M

The given number = 77548 M

For a number to be divisible by 9 sum of its digits must be divisible by 9.

Sum of its given digits = 7 + 7 + 5 + 4 + 8 = 31

The number next to 31, which is divisible by 9 is 36

Required smallest number = 36 - 31 = 5

Therefore , value of M is 5.

(iii) 627 M 9

The given number = 627 M 9

For a number to be divisible by 9 sum of its digits must be divisible by 9.

Sum of its given digits = 6 + 7 + 2 + 9 = 24

The number next to 24, which is divisible by 9 is 27

Required smallest number = 27 - 24 = 3

Therefore , value of M is 3.

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subject-cta
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