Selina solutions

Selina solutions

Grade 6

Natural Numbers and Whole Numbers (Including Patterns) | Exercise 5(C)

Question 1

Q1) Fill in the blanks:

(i) 42\times0=..........

(ii) 592\times1=.........

(iii) 328\times572=..........\times328

(iv) 229\times...........=578\times229

(v) 32\times15=32\times6+32\times7+32\times.........

(vi) 23\times56=20\times56+.......\times56

(vii) 83\times54+83\times16=83\times\left(..........\right)=83\times.......=.........

(viii) 98\times273-75\times273=\left(.........\right)\times273=..........\times273

Solution 1:

(i) 42 × 0 = 0

By closure property 0

(ii) 592 × 1 = 592

By closure property 1

(iii) 328 × 573 = 573 × 328

By commutative law of multiplication

(iv) 229 × 578 = 578 × 229

By commutative law of multiplication

(v) 32 × 15 = 32 × 6 + 32 × 7 + 32 × 2

By commutative law of multiplication

(vi) 23 × 56 = 20 × 56 + 3 × 56

By distributive law of multiplication

(vii) 83 × 54 + 83 × 16 = 83 × (54 + 16) = 83 × 70 = 5810

(viii) 98 × 273 – 75 × 273 = (98 - 75) × 273 = 23 × 273

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subject-cta

Question 1

Q1) Fill in the blanks:

(i) 42\times0=..........

(ii) 592\times1=.........

(iii) 328\times572=..........\times328

(iv) 229\times...........=578\times229

(v) 32\times15=32\times6+32\times7+32\times.........

(vi) 23\times56=20\times56+.......\times56

(vii) 83\times54+83\times16=83\times\left(..........\right)=83\times.......=.........

(viii) 98\times273-75\times273=\left(.........\right)\times273=..........\times273

Solution 1:

(i) 42 × 0 = 0

By closure property 0

(ii) 592 × 1 = 592

By closure property 1

(iii) 328 × 573 = 573 × 328

By commutative law of multiplication

(iv) 229 × 578 = 578 × 229

By commutative law of multiplication

(v) 32 × 15 = 32 × 6 + 32 × 7 + 32 × 2

By commutative law of multiplication

(vi) 23 × 56 = 20 × 56 + 3 × 56

By distributive law of multiplication

(vii) 83 × 54 + 83 × 16 = 83 × (54 + 16) = 83 × 70 = 5810

(viii) 98 × 273 – 75 × 273 = (98 - 75) × 273 = 23 × 273

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subject-cta
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